3.7.47 \(\int \frac {(d f+e f x)^3}{(a+b (d+e x)^2+c (d+e x)^4)^2} \, dx\) [647]

Optimal. Leaf size=103 \[ \frac {f^3 \left (2 a+b (d+e x)^2\right )}{2 \left (b^2-4 a c\right ) e \left (a+b (d+e x)^2+c (d+e x)^4\right )}-\frac {b f^3 \tanh ^{-1}\left (\frac {b+2 c (d+e x)^2}{\sqrt {b^2-4 a c}}\right )}{\left (b^2-4 a c\right )^{3/2} e} \]

[Out]

1/2*f^3*(2*a+b*(e*x+d)^2)/(-4*a*c+b^2)/e/(a+b*(e*x+d)^2+c*(e*x+d)^4)-b*f^3*arctanh((b+2*c*(e*x+d)^2)/(-4*a*c+b
^2)^(1/2))/(-4*a*c+b^2)^(3/2)/e

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Rubi [A]
time = 0.10, antiderivative size = 103, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, integrand size = 33, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.152, Rules used = {1156, 1128, 652, 632, 212} \begin {gather*} \frac {f^3 \left (2 a+b (d+e x)^2\right )}{2 e \left (b^2-4 a c\right ) \left (a+b (d+e x)^2+c (d+e x)^4\right )}-\frac {b f^3 \tanh ^{-1}\left (\frac {b+2 c (d+e x)^2}{\sqrt {b^2-4 a c}}\right )}{e \left (b^2-4 a c\right )^{3/2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(d*f + e*f*x)^3/(a + b*(d + e*x)^2 + c*(d + e*x)^4)^2,x]

[Out]

(f^3*(2*a + b*(d + e*x)^2))/(2*(b^2 - 4*a*c)*e*(a + b*(d + e*x)^2 + c*(d + e*x)^4)) - (b*f^3*ArcTanh[(b + 2*c*
(d + e*x)^2)/Sqrt[b^2 - 4*a*c]])/((b^2 - 4*a*c)^(3/2)*e)

Rule 212

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))*ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 632

Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> Dist[-2, Subst[Int[1/Simp[b^2 - 4*a*c - x^2, x], x]
, x, b + 2*c*x], x] /; FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rule 652

Int[((d_.) + (e_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[((b*d - 2*a*e + (2*c*d -
b*e)*x)/((p + 1)*(b^2 - 4*a*c)))*(a + b*x + c*x^2)^(p + 1), x] - Dist[(2*p + 3)*((2*c*d - b*e)/((p + 1)*(b^2 -
4*a*c))), Int[(a + b*x + c*x^2)^(p + 1), x], x] /; FreeQ[{a, b, c, d, e}, x] && NeQ[2*c*d - b*e, 0] && NeQ[b^
2 - 4*a*c, 0] && LtQ[p, -1] && NeQ[p, -3/2]

Rule 1128

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^2 + (c_.)*(x_)^4)^(p_.), x_Symbol] :> Dist[1/2, Subst[Int[x^((m - 1)/2)*(a +
b*x + c*x^2)^p, x], x, x^2], x] /; FreeQ[{a, b, c, p}, x] && IntegerQ[(m - 1)/2]

Rule 1156

Int[(u_)^(m_.)*((a_.) + (b_.)*(v_)^2 + (c_.)*(v_)^4)^(p_.), x_Symbol] :> Dist[u^m/(Coefficient[v, x, 1]*v^m),
Subst[Int[x^m*(a + b*x^2 + c*x^(2*2))^p, x], x, v], x] /; FreeQ[{a, b, c, m, p}, x] && LinearPairQ[u, v, x]

Rubi steps

\begin {align*} \int \frac {(d f+e f x)^3}{\left (a+b (d+e x)^2+c (d+e x)^4\right )^2} \, dx &=\frac {f^3 \text {Subst}\left (\int \frac {x^3}{\left (a+b x^2+c x^4\right )^2} \, dx,x,d+e x\right )}{e}\\ &=\frac {f^3 \text {Subst}\left (\int \frac {x}{\left (a+b x+c x^2\right )^2} \, dx,x,(d+e x)^2\right )}{2 e}\\ &=\frac {f^3 \left (2 a+b (d+e x)^2\right )}{2 \left (b^2-4 a c\right ) e \left (a+b (d+e x)^2+c (d+e x)^4\right )}+\frac {\left (b f^3\right ) \text {Subst}\left (\int \frac {1}{a+b x+c x^2} \, dx,x,(d+e x)^2\right )}{2 \left (b^2-4 a c\right ) e}\\ &=\frac {f^3 \left (2 a+b (d+e x)^2\right )}{2 \left (b^2-4 a c\right ) e \left (a+b (d+e x)^2+c (d+e x)^4\right )}-\frac {\left (b f^3\right ) \text {Subst}\left (\int \frac {1}{b^2-4 a c-x^2} \, dx,x,b+2 c (d+e x)^2\right )}{\left (b^2-4 a c\right ) e}\\ &=\frac {f^3 \left (2 a+b (d+e x)^2\right )}{2 \left (b^2-4 a c\right ) e \left (a+b (d+e x)^2+c (d+e x)^4\right )}-\frac {b f^3 \tanh ^{-1}\left (\frac {b+2 c (d+e x)^2}{\sqrt {b^2-4 a c}}\right )}{\left (b^2-4 a c\right )^{3/2} e}\\ \end {align*}

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Mathematica [A]
time = 0.09, size = 103, normalized size = 1.00 \begin {gather*} \frac {f^3 \left (\frac {2 a+b (d+e x)^2}{\left (b^2-4 a c\right ) \left (a+(d+e x)^2 \left (b+c (d+e x)^2\right )\right )}-\frac {2 b \tan ^{-1}\left (\frac {b+2 c (d+e x)^2}{\sqrt {-b^2+4 a c}}\right )}{\left (-b^2+4 a c\right )^{3/2}}\right )}{2 e} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(d*f + e*f*x)^3/(a + b*(d + e*x)^2 + c*(d + e*x)^4)^2,x]

[Out]

(f^3*((2*a + b*(d + e*x)^2)/((b^2 - 4*a*c)*(a + (d + e*x)^2*(b + c*(d + e*x)^2))) - (2*b*ArcTan[(b + 2*c*(d +
e*x)^2)/Sqrt[-b^2 + 4*a*c]])/(-b^2 + 4*a*c)^(3/2)))/(2*e)

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Maple [C] Result contains higher order function than in optimal. Order 9 vs. order 3.
time = 0.23, size = 280, normalized size = 2.72

method	result	size
default	\(f^{3} \left (\frac {-\frac {x^{2} b e}{2 \left (4 a c -b^{2}\right )}-\frac {x b d}{4 a c -b^{2}}-\frac {d^{2} b +2 a}{2 e \left (4 a c -b^{2}\right )}}{c \,e^{4} x^{4}+4 c d \,e^{3} x^{3}+6 c \,d^{2} e^{2} x^{2}+4 c \,d^{3} e x +b \,e^{2} x^{2}+d^{4} c +2 d e b x +d^{2} b +a}+\frac {b \left (\munderset {\textit {\_R} =\RootOf \left (e^{4} c \,\textit {\_Z}^{4}+4 d \,e^{3} c \,\textit {\_Z}^{3}+\left (6 d^{2} e^{2} c +e^{2} b \right ) \textit {\_Z}^{2}+\left (4 d^{3} e c +2 d e b \right ) \textit {\_Z} +d^{4} c +d^{2} b +a \right )}{\sum }\frac {\left (-\textit {\_R} e -d \right ) \ln \left (x -\textit {\_R} \right )}{2 e^{3} c \,\textit {\_R}^{3}+6 d \,e^{2} c \,\textit {\_R}^{2}+6 c \,d^{2} e \textit {\_R} +2 c \,d^{3}+e b \textit {\_R} +b d}\right )}{2 \left (4 a c -b^{2}\right ) e}\right )\)	\(280\)
risch	\(\frac {-\frac {b e \,f^{3} x^{2}}{2 \left (4 a c -b^{2}\right )}-\frac {b d \,f^{3} x}{4 a c -b^{2}}-\frac {f^{3} \left (d^{2} b +2 a \right )}{2 e \left (4 a c -b^{2}\right )}}{c \,e^{4} x^{4}+4 c d \,e^{3} x^{3}+6 c \,d^{2} e^{2} x^{2}+4 c \,d^{3} e x +b \,e^{2} x^{2}+d^{4} c +2 d e b x +d^{2} b +a}+\frac {f^{3} b \ln \left (\left (-\left (-4 a c +b^{2}\right )^{\frac {3}{2}} e^{2}+4 a b c \,e^{2}-b^{3} e^{2}\right ) x^{2}+\left (-2 \left (-4 a c +b^{2}\right )^{\frac {3}{2}} d e +8 a b c d e -2 b^{3} d e \right ) x -\left (-4 a c +b^{2}\right )^{\frac {3}{2}} d^{2}+4 a b c \,d^{2}-b^{3} d^{2}+8 a^{2} c -2 a \,b^{2}\right )}{2 \left (-4 a c +b^{2}\right )^{\frac {3}{2}} e}-\frac {f^{3} b \ln \left (\left (-\left (-4 a c +b^{2}\right )^{\frac {3}{2}} e^{2}-4 a b c \,e^{2}+b^{3} e^{2}\right ) x^{2}+\left (-2 \left (-4 a c +b^{2}\right )^{\frac {3}{2}} d e -8 a b c d e +2 b^{3} d e \right ) x -\left (-4 a c +b^{2}\right )^{\frac {3}{2}} d^{2}-4 a b c \,d^{2}+b^{3} d^{2}-8 a^{2} c +2 a \,b^{2}\right )}{2 \left (-4 a c +b^{2}\right )^{\frac {3}{2}} e}\)	\(401\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((e*f*x+d*f)^3/(a+b*(e*x+d)^2+c*(e*x+d)^4)^2,x,method=_RETURNVERBOSE)

[Out]

f^3*((-1/2/(4*a*c-b^2)*x^2*b*e-1/(4*a*c-b^2)*x*b*d-1/2/e*(b*d^2+2*a)/(4*a*c-b^2))/(c*e^4*x^4+4*c*d*e^3*x^3+6*c
*d^2*e^2*x^2+4*c*d^3*e*x+b*e^2*x^2+c*d^4+2*b*d*e*x+b*d^2+a)+1/2*b/(4*a*c-b^2)/e*sum((-_R*e-d)/(2*_R^3*c*e^3+6*
_R^2*c*d*e^2+6*_R*c*d^2*e+2*c*d^3+_R*b*e+b*d)*ln(x-_R),_R=RootOf(e^4*c*_Z^4+4*d*e^3*c*_Z^3+(6*c*d^2*e^2+b*e^2)
*_Z^2+(4*c*d^3*e+2*b*d*e)*_Z+d^4*c+d^2*b+a)))

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*f*x+d*f)^3/(a+b*(e*x+d)^2+c*(e*x+d)^4)^2,x, algorithm="maxima")

[Out]

b*f^3*integrate((x*e + d)/(c*x^4*e^4 + 4*c*d*x^3*e^3 + c*d^4 + b*d^2 + (6*c*d^2*e^2 + b*e^2)*x^2 + 2*(2*c*d^3*
e + b*d*e)*x + a), x)/(b^2 - 4*a*c) + 1/2*(b*f^3*x^2*e^2 + 2*b*d*f^3*x*e + (b*d^2 + 2*a)*f^3)/((b^2*c*e - 4*a*
c^2*e)*d^4 + 4*(b^2*c*e^4 - 4*a*c^2*e^4)*d*x^3 + (b^2*c*e^5 - 4*a*c^2*e^5)*x^4 + a*b^2*e - 4*a^2*c*e + (b^3*e
- 4*a*b*c*e)*d^2 + (b^3*e^3 - 4*a*b*c*e^3 + 6*(b^2*c*e^3 - 4*a*c^2*e^3)*d^2)*x^2 + 2*(2*(b^2*c*e^2 - 4*a*c^2*e
^2)*d^3 + (b^3*e^2 - 4*a*b*c*e^2)*d)*x)

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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 468 vs. \(2 (99) = 198\).
time = 0.39, size = 1063, normalized size = 10.32 \begin {gather*} \left [\frac {{\left (b^{3} - 4 \, a b c\right )} f^{3} x^{2} e^{2} + 2 \, {\left (b^{3} - 4 \, a b c\right )} d f^{3} x e + {\left (2 \, a b^{2} - 8 \, a^{2} c + {\left (b^{3} - 4 \, a b c\right )} d^{2}\right )} f^{3} - {\left (b c f^{3} x^{4} e^{4} + 4 \, b c d f^{3} x^{3} e^{3} + {\left (6 \, b c d^{2} + b^{2}\right )} f^{3} x^{2} e^{2} + 2 \, {\left (2 \, b c d^{3} + b^{2} d\right )} f^{3} x e + {\left (b c d^{4} + b^{2} d^{2} + a b\right )} f^{3}\right )} \sqrt {b^{2} - 4 \, a c} \log \left (\frac {2 \, c^{2} x^{4} e^{4} + 8 \, c^{2} d x^{3} e^{3} + 2 \, c^{2} d^{4} + 2 \, b c d^{2} + 2 \, {\left (6 \, c^{2} d^{2} + b c\right )} x^{2} e^{2} + 4 \, {\left (2 \, c^{2} d^{3} + b c d\right )} x e + b^{2} - 2 \, a c + {\left (2 \, c x^{2} e^{2} + 4 \, c d x e + 2 \, c d^{2} + b\right )} \sqrt {b^{2} - 4 \, a c}}{c x^{4} e^{4} + 4 \, c d x^{3} e^{3} + c d^{4} + {\left (6 \, c d^{2} + b\right )} x^{2} e^{2} + b d^{2} + 2 \, {\left (2 \, c d^{3} + b d\right )} x e + a}\right )}{2 \, {\left ({\left (b^{4} c - 8 \, a b^{2} c^{2} + 16 \, a^{2} c^{3}\right )} x^{4} e^{5} + 4 \, {\left (b^{4} c - 8 \, a b^{2} c^{2} + 16 \, a^{2} c^{3}\right )} d x^{3} e^{4} + {\left (b^{5} - 8 \, a b^{3} c + 16 \, a^{2} b c^{2} + 6 \, {\left (b^{4} c - 8 \, a b^{2} c^{2} + 16 \, a^{2} c^{3}\right )} d^{2}\right )} x^{2} e^{3} + 2 \, {\left (2 \, {\left (b^{4} c - 8 \, a b^{2} c^{2} + 16 \, a^{2} c^{3}\right )} d^{3} + {\left (b^{5} - 8 \, a b^{3} c + 16 \, a^{2} b c^{2}\right )} d\right )} x e^{2} + {\left (a b^{4} - 8 \, a^{2} b^{2} c + 16 \, a^{3} c^{2} + {\left (b^{4} c - 8 \, a b^{2} c^{2} + 16 \, a^{2} c^{3}\right )} d^{4} + {\left (b^{5} - 8 \, a b^{3} c + 16 \, a^{2} b c^{2}\right )} d^{2}\right )} e\right )}}, \frac {{\left (b^{3} - 4 \, a b c\right )} f^{3} x^{2} e^{2} + 2 \, {\left (b^{3} - 4 \, a b c\right )} d f^{3} x e + {\left (2 \, a b^{2} - 8 \, a^{2} c + {\left (b^{3} - 4 \, a b c\right )} d^{2}\right )} f^{3} - 2 \, {\left (b c f^{3} x^{4} e^{4} + 4 \, b c d f^{3} x^{3} e^{3} + {\left (6 \, b c d^{2} + b^{2}\right )} f^{3} x^{2} e^{2} + 2 \, {\left (2 \, b c d^{3} + b^{2} d\right )} f^{3} x e + {\left (b c d^{4} + b^{2} d^{2} + a b\right )} f^{3}\right )} \sqrt {-b^{2} + 4 \, a c} \arctan \left (-\frac {{\left (2 \, c x^{2} e^{2} + 4 \, c d x e + 2 \, c d^{2} + b\right )} \sqrt {-b^{2} + 4 \, a c}}{b^{2} - 4 \, a c}\right )}{2 \, {\left ({\left (b^{4} c - 8 \, a b^{2} c^{2} + 16 \, a^{2} c^{3}\right )} x^{4} e^{5} + 4 \, {\left (b^{4} c - 8 \, a b^{2} c^{2} + 16 \, a^{2} c^{3}\right )} d x^{3} e^{4} + {\left (b^{5} - 8 \, a b^{3} c + 16 \, a^{2} b c^{2} + 6 \, {\left (b^{4} c - 8 \, a b^{2} c^{2} + 16 \, a^{2} c^{3}\right )} d^{2}\right )} x^{2} e^{3} + 2 \, {\left (2 \, {\left (b^{4} c - 8 \, a b^{2} c^{2} + 16 \, a^{2} c^{3}\right )} d^{3} + {\left (b^{5} - 8 \, a b^{3} c + 16 \, a^{2} b c^{2}\right )} d\right )} x e^{2} + {\left (a b^{4} - 8 \, a^{2} b^{2} c + 16 \, a^{3} c^{2} + {\left (b^{4} c - 8 \, a b^{2} c^{2} + 16 \, a^{2} c^{3}\right )} d^{4} + {\left (b^{5} - 8 \, a b^{3} c + 16 \, a^{2} b c^{2}\right )} d^{2}\right )} e\right )}}\right ] \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*f*x+d*f)^3/(a+b*(e*x+d)^2+c*(e*x+d)^4)^2,x, algorithm="fricas")

[Out]

[1/2*((b^3 - 4*a*b*c)*f^3*x^2*e^2 + 2*(b^3 - 4*a*b*c)*d*f^3*x*e + (2*a*b^2 - 8*a^2*c + (b^3 - 4*a*b*c)*d^2)*f^
3 - (b*c*f^3*x^4*e^4 + 4*b*c*d*f^3*x^3*e^3 + (6*b*c*d^2 + b^2)*f^3*x^2*e^2 + 2*(2*b*c*d^3 + b^2*d)*f^3*x*e + (
b*c*d^4 + b^2*d^2 + a*b)*f^3)*sqrt(b^2 - 4*a*c)*log((2*c^2*x^4*e^4 + 8*c^2*d*x^3*e^3 + 2*c^2*d^4 + 2*b*c*d^2 +
2*(6*c^2*d^2 + b*c)*x^2*e^2 + 4*(2*c^2*d^3 + b*c*d)*x*e + b^2 - 2*a*c + (2*c*x^2*e^2 + 4*c*d*x*e + 2*c*d^2 +
b)*sqrt(b^2 - 4*a*c))/(c*x^4*e^4 + 4*c*d*x^3*e^3 + c*d^4 + (6*c*d^2 + b)*x^2*e^2 + b*d^2 + 2*(2*c*d^3 + b*d)*x
*e + a)))/((b^4*c - 8*a*b^2*c^2 + 16*a^2*c^3)*x^4*e^5 + 4*(b^4*c - 8*a*b^2*c^2 + 16*a^2*c^3)*d*x^3*e^4 + (b^5
- 8*a*b^3*c + 16*a^2*b*c^2 + 6*(b^4*c - 8*a*b^2*c^2 + 16*a^2*c^3)*d^2)*x^2*e^3 + 2*(2*(b^4*c - 8*a*b^2*c^2 + 1
6*a^2*c^3)*d^3 + (b^5 - 8*a*b^3*c + 16*a^2*b*c^2)*d)*x*e^2 + (a*b^4 - 8*a^2*b^2*c + 16*a^3*c^2 + (b^4*c - 8*a*
b^2*c^2 + 16*a^2*c^3)*d^4 + (b^5 - 8*a*b^3*c + 16*a^2*b*c^2)*d^2)*e), 1/2*((b^3 - 4*a*b*c)*f^3*x^2*e^2 + 2*(b^
3 - 4*a*b*c)*d*f^3*x*e + (2*a*b^2 - 8*a^2*c + (b^3 - 4*a*b*c)*d^2)*f^3 - 2*(b*c*f^3*x^4*e^4 + 4*b*c*d*f^3*x^3*
e^3 + (6*b*c*d^2 + b^2)*f^3*x^2*e^2 + 2*(2*b*c*d^3 + b^2*d)*f^3*x*e + (b*c*d^4 + b^2*d^2 + a*b)*f^3)*sqrt(-b^2
+ 4*a*c)*arctan(-(2*c*x^2*e^2 + 4*c*d*x*e + 2*c*d^2 + b)*sqrt(-b^2 + 4*a*c)/(b^2 - 4*a*c)))/((b^4*c - 8*a*b^2
*c^2 + 16*a^2*c^3)*x^4*e^5 + 4*(b^4*c - 8*a*b^2*c^2 + 16*a^2*c^3)*d*x^3*e^4 + (b^5 - 8*a*b^3*c + 16*a^2*b*c^2
+ 6*(b^4*c - 8*a*b^2*c^2 + 16*a^2*c^3)*d^2)*x^2*e^3 + 2*(2*(b^4*c - 8*a*b^2*c^2 + 16*a^2*c^3)*d^3 + (b^5 - 8*a
*b^3*c + 16*a^2*b*c^2)*d)*x*e^2 + (a*b^4 - 8*a^2*b^2*c + 16*a^3*c^2 + (b^4*c - 8*a*b^2*c^2 + 16*a^2*c^3)*d^4 +
(b^5 - 8*a*b^3*c + 16*a^2*b*c^2)*d^2)*e)]

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Sympy [B] Leaf count of result is larger than twice the leaf count of optimal. 556 vs. \(2 (88) = 176\).
time = 2.94, size = 556, normalized size = 5.40 \begin {gather*} \frac {b f^{3} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{3}}} \log {\left (\frac {2 d x}{e} + x^{2} + \frac {- 16 a^{2} b c^{2} f^{3} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{3}}} + 8 a b^{3} c f^{3} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{3}}} - b^{5} f^{3} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{3}}} + b^{2} f^{3} + 2 b c d^{2} f^{3}}{2 b c e^{2} f^{3}} \right )}}{2 e} - \frac {b f^{3} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{3}}} \log {\left (\frac {2 d x}{e} + x^{2} + \frac {16 a^{2} b c^{2} f^{3} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{3}}} - 8 a b^{3} c f^{3} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{3}}} + b^{5} f^{3} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{3}}} + b^{2} f^{3} + 2 b c d^{2} f^{3}}{2 b c e^{2} f^{3}} \right )}}{2 e} + \frac {- 2 a f^{3} - b d^{2} f^{3} - 2 b d e f^{3} x - b e^{2} f^{3} x^{2}}{8 a^{2} c e - 2 a b^{2} e + 8 a b c d^{2} e + 8 a c^{2} d^{4} e - 2 b^{3} d^{2} e - 2 b^{2} c d^{4} e + x^{4} \cdot \left (8 a c^{2} e^{5} - 2 b^{2} c e^{5}\right ) + x^{3} \cdot \left (32 a c^{2} d e^{4} - 8 b^{2} c d e^{4}\right ) + x^{2} \cdot \left (8 a b c e^{3} + 48 a c^{2} d^{2} e^{3} - 2 b^{3} e^{3} - 12 b^{2} c d^{2} e^{3}\right ) + x \left (16 a b c d e^{2} + 32 a c^{2} d^{3} e^{2} - 4 b^{3} d e^{2} - 8 b^{2} c d^{3} e^{2}\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*f*x+d*f)**3/(a+b*(e*x+d)**2+c*(e*x+d)**4)**2,x)

[Out]

b*f**3*sqrt(-1/(4*a*c - b**2)**3)*log(2*d*x/e + x**2 + (-16*a**2*b*c**2*f**3*sqrt(-1/(4*a*c - b**2)**3) + 8*a*
b**3*c*f**3*sqrt(-1/(4*a*c - b**2)**3) - b**5*f**3*sqrt(-1/(4*a*c - b**2)**3) + b**2*f**3 + 2*b*c*d**2*f**3)/(
2*b*c*e**2*f**3))/(2*e) - b*f**3*sqrt(-1/(4*a*c - b**2)**3)*log(2*d*x/e + x**2 + (16*a**2*b*c**2*f**3*sqrt(-1/
(4*a*c - b**2)**3) - 8*a*b**3*c*f**3*sqrt(-1/(4*a*c - b**2)**3) + b**5*f**3*sqrt(-1/(4*a*c - b**2)**3) + b**2*
f**3 + 2*b*c*d**2*f**3)/(2*b*c*e**2*f**3))/(2*e) + (-2*a*f**3 - b*d**2*f**3 - 2*b*d*e*f**3*x - b*e**2*f**3*x**
2)/(8*a**2*c*e - 2*a*b**2*e + 8*a*b*c*d**2*e + 8*a*c**2*d**4*e - 2*b**3*d**2*e - 2*b**2*c*d**4*e + x**4*(8*a*c
**2*e**5 - 2*b**2*c*e**5) + x**3*(32*a*c**2*d*e**4 - 8*b**2*c*d*e**4) + x**2*(8*a*b*c*e**3 + 48*a*c**2*d**2*e*
*3 - 2*b**3*e**3 - 12*b**2*c*d**2*e**3) + x*(16*a*b*c*d*e**2 + 32*a*c**2*d**3*e**2 - 4*b**3*d*e**2 - 8*b**2*c*
d**3*e**2))

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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 211 vs. \(2 (99) = 198\).
time = 3.67, size = 211, normalized size = 2.05 \begin {gather*} \frac {b f^{3} \arctan \left (\frac {2 \, c d^{2} f + 2 \, {\left (f x^{2} e + 2 \, d f x\right )} c e + b f}{\sqrt {-b^{2} + 4 \, a c} f}\right ) e^{\left (-1\right )}}{{\left (b^{2} - 4 \, a c\right )} \sqrt {-b^{2} + 4 \, a c}} + \frac {b d^{2} f^{5} + {\left (f x^{2} e + 2 \, d f x\right )} b f^{4} e + 2 \, a f^{5}}{2 \, {\left (c d^{4} f^{2} + 2 \, {\left (f x^{2} e + 2 \, d f x\right )} c d^{2} f e + b d^{2} f^{2} + {\left (f x^{2} e + 2 \, d f x\right )}^{2} c e^{2} + {\left (f x^{2} e + 2 \, d f x\right )} b f e + a f^{2}\right )} {\left (b^{2} e - 4 \, a c e\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*f*x+d*f)^3/(a+b*(e*x+d)^2+c*(e*x+d)^4)^2,x, algorithm="giac")

[Out]

b*f^3*arctan((2*c*d^2*f + 2*(f*x^2*e + 2*d*f*x)*c*e + b*f)/(sqrt(-b^2 + 4*a*c)*f))*e^(-1)/((b^2 - 4*a*c)*sqrt(
-b^2 + 4*a*c)) + 1/2*(b*d^2*f^5 + (f*x^2*e + 2*d*f*x)*b*f^4*e + 2*a*f^5)/((c*d^4*f^2 + 2*(f*x^2*e + 2*d*f*x)*c
*d^2*f*e + b*d^2*f^2 + (f*x^2*e + 2*d*f*x)^2*c*e^2 + (f*x^2*e + 2*d*f*x)*b*f*e + a*f^2)*(b^2*e - 4*a*c*e))

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Mupad [B]
time = 1.90, size = 460, normalized size = 4.47 \begin {gather*} \frac {b\,f^3\,\mathrm {atan}\left (\frac {{\left (4\,a\,c-b^2\right )}^4\,\left (x\,\left (\frac {b^3\,f^6\,\left (2\,b^3\,c^2\,d\,e^9-8\,a\,b\,c^3\,d\,e^9\right )}{a\,e^2\,{\left (4\,a\,c-b^2\right )}^{11/2}}-\frac {2\,b^2\,c^2\,d\,e^7\,f^6}{a\,{\left (4\,a\,c-b^2\right )}^{7/2}}\right )+x^2\,\left (\frac {b^3\,f^6\,\left (2\,b^3\,c^2\,e^{10}-8\,a\,b\,c^3\,e^{10}\right )}{2\,a\,e^2\,{\left (4\,a\,c-b^2\right )}^{11/2}}-\frac {b^2\,c^2\,e^8\,f^6}{a\,{\left (4\,a\,c-b^2\right )}^{7/2}}\right )-\frac {b^3\,f^6\,\left (16\,a^2\,c^3\,e^8-4\,a\,b^2\,c^2\,e^8+8\,a\,b\,c^3\,d^2\,e^8-2\,b^3\,c^2\,d^2\,e^8\right )}{2\,a\,e^2\,{\left (4\,a\,c-b^2\right )}^{11/2}}-\frac {b^2\,c^2\,d^2\,e^6\,f^6}{a\,{\left (4\,a\,c-b^2\right )}^{7/2}}\right )}{2\,b^2\,c^2\,e^6\,f^6}\right )}{e\,{\left (4\,a\,c-b^2\right )}^{3/2}}-\frac {\frac {f^3\,\left (b\,d^2+2\,a\right )}{2\,e\,\left (4\,a\,c-b^2\right )}+\frac {b\,d\,f^3\,x}{4\,a\,c-b^2}+\frac {b\,e\,f^3\,x^2}{2\,\left (4\,a\,c-b^2\right )}}{a+x^2\,\left (6\,c\,d^2\,e^2+b\,e^2\right )+b\,d^2+c\,d^4+x\,\left (4\,c\,e\,d^3+2\,b\,e\,d\right )+c\,e^4\,x^4+4\,c\,d\,e^3\,x^3} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((d*f + e*f*x)^3/(a + b*(d + e*x)^2 + c*(d + e*x)^4)^2,x)

[Out]

(b*f^3*atan(((4*a*c - b^2)^4*(x*((b^3*f^6*(2*b^3*c^2*d*e^9 - 8*a*b*c^3*d*e^9))/(a*e^2*(4*a*c - b^2)^(11/2)) -
(2*b^2*c^2*d*e^7*f^6)/(a*(4*a*c - b^2)^(7/2))) + x^2*((b^3*f^6*(2*b^3*c^2*e^10 - 8*a*b*c^3*e^10))/(2*a*e^2*(4*
a*c - b^2)^(11/2)) - (b^2*c^2*e^8*f^6)/(a*(4*a*c - b^2)^(7/2))) - (b^3*f^6*(16*a^2*c^3*e^8 - 4*a*b^2*c^2*e^8 -
2*b^3*c^2*d^2*e^8 + 8*a*b*c^3*d^2*e^8))/(2*a*e^2*(4*a*c - b^2)^(11/2)) - (b^2*c^2*d^2*e^6*f^6)/(a*(4*a*c - b^
2)^(7/2))))/(2*b^2*c^2*e^6*f^6)))/(e*(4*a*c - b^2)^(3/2)) - ((f^3*(2*a + b*d^2))/(2*e*(4*a*c - b^2)) + (b*d*f^
3*x)/(4*a*c - b^2) + (b*e*f^3*x^2)/(2*(4*a*c - b^2)))/(a + x^2*(b*e^2 + 6*c*d^2*e^2) + b*d^2 + c*d^4 + x*(2*b*
d*e + 4*c*d^3*e) + c*e^4*x^4 + 4*c*d*e^3*x^3)

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